对于OCM考试的几点意见和建议

Oracle Certified Master(OCM) 大师认证资质是Oracle认证的最高级别。此认证是对技术、知识和操作技能的最高级别的认可。Oracle认证大师是解决最困难的技术难题和最复杂的系 统故障的最佳Oracle专家人选。资深专家级Oracle 技能考试,通过后将成为企业内的资深专家和顾问。OCM 不但有能力处理关键业务数据库系统和应用,还能帮助客户解决所有的Oracle 技术困难。要想获得OCM 证书,必须先通过OCA、OCP考试,再学习两门高级技术课程,然后在Oracle 实验室通过场景实验考试。场景实验考试的目的是测试您的实际问题分析和故障解决能力。

作为一个过来人,我十分愿意分享我对备考OCM的几点建议:

这对于你来说既是一次考试,也是一次系统复习的好机会;OCM考试的面非常广,部分环节可能是你从未实践过的。
准备时间最好不要少于半年,但也千万不要超过半年。
准备阶段使用考纲指定的操作系统,DB,OMS,Clusterware版本。这里推荐在Redhat或Oracle Enterprise Linux 4.7平台上练习,切勿使用windows或windows远程登录练习。
2天的考试是对体力的考验,所以要保证充足的睡眠。
试卷分英语和日语两版;题目文字量较多,需认真阅读;如果对题意并不明了,可以让监考老师进一步解释,一般不会推辞。
很多考试中要求建立的对象可以通过OMS获得SQL语句,确认后输入到SQLPLUS中执行。
部分环节需要十分耐心,如果你不想在屏幕前焦急等待,可以去上个厕所或者泡杯咖啡,总之请放轻松。
如果你不熟悉Grid Control(OMS)界面,那么可以尝试读一下《Oracle.Enterprise.Manager.10g.Grid.Control.Implementation.Guide.2009》,并勤加练习。
考试期间可以阅读10g的官方文档,也可以查询metalink(MOS),前提是在你有足够时间的情况下。
安装配置Grid Control(OMS)是考试的一个高危阶段,这往往决定于你的安装配置经验以及人品,但是一旦出现了问题而你毫无troubleshooting Grid Control的能力,那么就显得事倍功半了。
考试后的hand on是一个”复杂的”过程,请致电OU的800电话。

to be continued …………

Does DB Time include wait on cpu queue time?

DB TIME1=DB CPU2+ Foreground NO-Idle wait time

1:Amount of elapsed time (in microseconds) spent performing Database user-level calls. This does not include the elapsed time spent on instance background processes such as PMON.

2:Amount of CPU time (in microseconds) spent on database user-level calls. This does not include the CPU time spent on instance background processes such as PMON.

10g中引入了基于时间统计信息的调优模型,其核心或者说最值得我们关心的大概是DB TIME和AASC 2项指标。DB TIME是Oracle在数据库层对用户级别(不包括后台进程的CPU和非空闲等待时间)各类操作耗时的一个总计,它直接反映了数据库前台的”工时”。DB TIME是否包含了前台进程在CPU队列上的等待时间呢,换而言之我们的命题是”Does DB TIME equal to DB CPU+Foreground NO-Idle wait time + DB CPU ON QUEUE ?”

让我们来看看以下测试:

[maclean@rh2 ~]$ cat /proc/cpuinfo |grep processor|wc -l
2
/*这是一台双核的pc服务器*/

打开session A:
begin
/* first one busy on cpu */
loop
null;
end loop;
end;
/*死循环调用NULL,会尝试独占一个逻辑CPU,没有其他等待事件*/

打开SESSION B:
begin
/* second one busy on cpu */
loop
null;
end loop;
end;

打开SESSION C:
begin
/* third one busy on cpu */
loop
null;
end loop;
end;

打开SESSION D:
SQL> exec dbms_workload_repository.create_snapshot;
PL/SQL procedure successfully completed.

/*手动收集AWR 快照*/

/*等待几分钟,以便收集信息*/

SQL> exec dbms_workload_repository.create_snapshot;
PL/SQL procedure successfully completed.
/*再次手动收集快照*/

我们来看看AWR报告中的Time Model Statistics:

DB TIME为344s,而DB CPU为226s。以上匿名PL/SQL块仅引起CPU争用(不会产生其他前台等待事件),而这里DB TIME要远大于DB CPU,可见DB TIME=DB CPU+Foreground wait time+Cpu on queue;  我们也可以观察以下OEM界面上的AAS图形:

ASH报告也正确反映了这一事实,虽然它把cpu time和wait on cpu queue归并做了Cpu+wait for CPU:

可以看到CPU ON QUEUE有时被计为Wait time部分。当以上3个回话同时执行CPU敏感的匿名块过程时,其瞬时的Average Session Count为3,而该pc服务器上只有2个逻辑CPU,可以认为实例在该短期内存出现严重阻塞,表现到OS层也就是短期内持续队列较高。

[maclean@rh2 ~]$ vmstat 2
procs -----------memory---------- ---swap-- -----io---- --system-- -----cpu------
 r  b   swpd   free   buff  cache   si   so    bi    bo   in   cs us sy id wa st
 3  0      0 752180  93912 2127440    0    0   194   168  536  302  6  1 90  3  0
 3  0      0 752056  93912 2127508    0    0     0     0 1012  661 100  0  0  0  0
 2  0      0 751436  93928 2127548    0    0     0   932 1131  750 99  1  0  0  0
 2  0      0 751436  93928 2127596    0    0     0    16 1012  644 99  0  0  0  0
 2  0      0 751444  93928 2127596    0    0     0     0 1011  695 100  0  0  0  0

11g 新特性IGNORE_ROW_ON_DUPKEY_INDEX提示

11g中引入一些功能强大的hint提示,其中就包括了IGNORE_ROW_ON_DUPKEY_INDEX。其官方定义为:
“The IGNORE_ROW_ON_DUPKEY_INDEX hint applies only to single-table INSERT operations. It is not supported for UPDATE, DELETE, MERGE, or multitable insert operations. IGNORE_ROW_ON_DUPKEY_INDEX  causes the statement to ignore a unique key violation for a specified set of columns or for a specified index. When a unique key violation is encountered, a row-level rollback occurs and execution resumes with the next input row. If you specify this hint when inserting data with DML error logging enabled, then the unique key violation is not logged and does not cause statement termination.”

针对具有唯一性约束的键,若程序设计时没有考虑到插入具有重复键值的行会引发ORA-00001 unique constraint violated错误,进而可能导致程序过程终止的问题的话;直接修改程序将会是十分复杂的工程。所幸我们在11g中有了”IGNORE_ROW_ON_DUPKEY_INDEX”提示,在INSERT单表的语句中加入该hint可以让Oracle静默地(silently)忽略那些具有重复键值的插入行,而不触发ORA-00001错误,允许程序继续运行下去,这可以说是一种十分简便的折中方案。要在生产环境中使用该特性,我们有必要对比一下其同使用Exception处理违反唯一约束间的性能差别。

SQL> drop table youyus ;

Table dropped.

SQL> create table youyus (t1 int ,t2 varchar2(20),t3 varchar2(30)) tablespace users;

Table created

SQL> create unique index youyus_uk on youyus(t1) tablespace users;

Index created
/*清理现场,添加唯一约束索引*/

SQL> alter system set optimizer_dynamic_sampling=1;

System altered.

SQL> alter system flush shared_pool;

System altered.

SQL> alter system flush buffer_cache;

System altered.

/* 以下过程在0-30000的整数内随机取200000次值,可以确保尝试INSERT大量重复t1键值的行,
以便测试使用DUP_VAL_ON_INDEX Exception时的各项性能参数;此处以及之后我们都将commit置于loop循环外,
从而避免大量commit影响我们的实验结果*/

declare
  rnd int;
begin
  /* 使用exception处理重复键值插入违反约束的问题*/
  for i in 1 .. 200000 loop
    BEGIN
      select round(dbms_random.value * 30000) into rnd from dual;
      insert into youyus
        (t1, t2, t3)
      values
        (rnd, 'DUPLICATE', 'INSERT TEST');
    exception
      when DUP_VAL_ON_INDEX then
        continue;
    end;
  end loop;
  commit;
end;

SQL> select plsql_exec_time,cpu_time,elapsed_time,user_io_wait_time from v$sql where sql_text like 'declare%exception%';

PLSQL_EXEC_TIME   CPU_TIME ELAPSED_TIME USER_IO_WAIT_TIME
--------------- ---------- ------------ -----------------
        4392268   88296566     92345066            621020
/* 逝去时间92s,CPU时间为88s,PLSQL执行时间4s*/

SQL> select count(*) from youyus;

  COUNT(*)
----------
     29958

SQL> truncate table youyus;

Table truncated.

SQL> alter system flush shared_pool;

System altered.

SQL> alter system flush buffer_cache;

System altered.

/* 在插入前判断插入值是否违反唯一约束应当是一种不错的想法,不过写起来多少有些"麻烦"*/

declare
  dup_count int;
  rnd       int;
begin
   /* 使用插入前判断(check before insert)是否违反唯一约束的方式*/
  for i in 1 .. 200000 loop
    BEGIN
      select round(dbms_random.value * 30000) into rnd from dual;
      select count(*) into dup_count from youyus where t1 = rnd;
      IF (dup_count = 0) then
        insert into youyus
          (t1, t2, t3)
        values
          (rnd, 'DUPLICATE', 'INSERT TEST');
      END IF;
    END;
  END LOOP;
  commit;
end;

SQL> select plsql_exec_time,cpu_time,elapsed_time,user_io_wait_time  from v$sql where sql_text like 'declare%check%';

PLSQL_EXEC_TIME   CPU_TIME ELAPSED_TIME USER_IO_WAIT_TIME
--------------- ---------- ------------ -----------------
        2153769   15709301     18265730            679813

/* PLSQL执行时间缩短到2s,整个过程的CPU时间大幅减少到15s*/
/***  以上对比可以得出Exception处理是一种CPU敏感操作的结论  ***/

SQL> select count(*) from youyus;

  COUNT(*)
----------
     29968

SQL> truncate table youyus;

Table truncated.

SQL> alter system flush shared_pool;

System altered.

SQL> alter system flush buffer_cache;

System altered.

declare
  rnd int;
begin
/* 使用IGNORE_ROW_ON_DUPKEY_INDEX hint方式*/
  for i in 1 .. 200000 loop
    select round(dbms_random.value * 30000) into rnd from dual;
    insert /*+ IGNORE_ROW_ON_DUPKEY_INDEX(YOUYUS,YOUYUS_UK) */
    into youyus
      (t1, t2, t3)
    values
      (rnd, 'DUPLICATE', 'INSERT TEST');
  end loop;
  commit;
end;

SQL> select plsql_exec_time,cpu_time,elapsed_time,user_io_wait_time  from v$sql where sql_text like 'declare%IGNORE%';

PLSQL_EXEC_TIME   CPU_TIME ELAPSED_TIME USER_IO_WAIT_TIME
--------------- ---------- ------------ -----------------
        2377262   78452903     84209306            623539

SQL> select count(*) from youyus;

  COUNT(*)
----------
     29959

/*** 
IGNORE_ROW_ON_DUPKEY_INDEX hint模式下,
CPU_TIME对比Exception模式时减少11%,但仍远高于插入前预检查模式;
就修改程序的复杂度而言IGNORE_ROW_ON_DUPKEY_INDEX模式要低于使用Exception模式,
而Exception模式又要低于CHECK_BEFORE_INSERT模式;CHECK_BEFORE_INSERT模式的CPU成本最低,但修改程序时的成本时间最高 
                                                                                                  ***/

/*需要注意的是IGNORE_ROW_ON_DUPKEY_INDEX提示与我们以往使用的hint略有不同,不正确使用它将导致报错*/

declare
  rnd int;
begin
/* 使用IGNORE_ROW_ON_DUPKEY_INDEX hint方式*/
  for i in 1 .. 200000 loop
    select round(dbms_random.value * 30000) into rnd from dual;
    insert /*+ IGNORE_ROW_ON_DUPKEY_INDEX(YOUYUS,I_AM_ERROR) */
    into youyus
      (t1, t2, t3)
    values
      (rnd, 'DUPLICATE', 'INSERT TEST');
  end loop;
  commit;
end;
/
ERROR at line 1:
ORA-38913: Index specified in the index hint is invalid
ORA-06512: at line 7

上述三者各环节耗时图示:

总结一句,IGNORE_ROW_ON_DUPKEY_INDEX为lazy developer专备。

8i查询DBA_FREE_SPACE视图极慢的问题

还是那套古老的8.1.7.4,在该系统上检查表空间使用情况的SQL运行缓慢,其SQL如下:

SELECT D.TABLESPACE_NAME,
       SPACE "SUM_SPACE(M)",
       SPACE - NVL(FREE_SPACE, 0) "USED_SPACE(M)",
       ROUND((1 - NVL(FREE_SPACE, 0) / SPACE) * 100, 2) "USED_RATE(%)",
       FREE_SPACE "FREE_SPACE(M)"
  FROM (SELECT TABLESPACE_NAME, ROUND(SUM(BYTES) / (1024 * 1024), 2) SPACE
          FROM DBA_DATA_FILES
         GROUP BY TABLESPACE_NAME) D,
       (SELECT TABLESPACE_NAME,
               ROUND(SUM(BYTES) / (1024 * 1024), 2) FREE_SPACE
          FROM DBA_FREE_SPACE
         GROUP BY TABLESPACE_NAME) F
 where d.tablespace_name = f.tablespace_name(+)
 order by "USED_RATE(%)" desc;
/*很面熟的DBA常用脚本吧?*/

经确认其中对DBA_FREE_SPACE视图的查询耗费了大量时间,8i中该视图的默认定义是:

select ts.name,
       fi.file#,
       f.block#,
       f.length * ts.blocksize,
       f.length,
       f.file#
  from sys.ts$ ts, sys.fet$ f, sys.file$ fi
 where ts.ts# = f.ts#
   and f.ts# = fi.ts#
   and f.file# = fi.relfile#
   and ts.bitmapped = 0
/*以上查询DMT表空间上的FREE EXTENT*/
union all
/*以下查询LMT表空间上的FREE EXTENT*/
select /*+ ordered use_nl(f) use_nl(fi) */
 ts.name,
 fi.file#,
 f.ktfbfebno,
 f.ktfbfeblks * ts.blocksize,
 f.ktfbfeblks,
 f.ktfbfefno
  from sys.ts$ ts, sys.x$ktfbfe f, sys.file$ fi
 where ts.ts# = f.ktfbfetsn
   and f.ktfbfetsn = fi.ts#
   and f.ktfbfefno = fi.relfile#
   and ts.bitmapped <> 0
   and ts.online$ in (1, 4)
   and ts.contents$ = 0

/*也许你感到奇怪,实际上8i中就有了本地管理模式的表空间了,只是很少有人用。("In Oracle 8i the EXTENT MANAGEMENT clause was introduced into the CREATE TABLESPACE statement allowing extent management to be LOCAL or DICTIONARY. Locally Manages Tablespaces (LMT) have a bitmap of the blocks, or groups of blocks, they contain allowing them to track extent allocation without reference to the data dictionary.")*/

/*因字典管理模式下FET$基表往往较大,导致UNION ALL以上部分在连接操作时会产生大量的逻辑读,最终导致了对DBA_FREE_SPACE视图的查询十分缓慢。*/

Oracle 提供了官方的视图并不意味着我们非它不可用,可以通过修改DBA_FREE_SPACE的定义,或另建一个具有相同功能但查询SQL构造不同的视图来加快查询速度:

explain plan for

select /*+use_hash (tsfi, fet2 ) */

 tsfi.tablespace_name,

 tsfi.file_id,

 fet2.block_id,

 tsfi.blocksize * fet2.blocks,

 fet2.blocks,

 tsfi.relfile#

  from (select /*+ use_hash ( ts, fi ) */

         ts.name      tablespace_name,

         fi.file#     file_id,

         ts.BLOCKSIZE,

         fi.relfile#,

         ts.ts#

          from sys.ts$ ts, sys.file$ fi

         where ts.ts# = fi.ts#

           and ts.online$ in (1, 4)) tsfi,

       (select f.block# block_id, f.length blocks, f.file# file_id, f.ts#

          from sys.fet$ f

        union all

        select f.ktfbfebno  block_id,

               f.ktfbfeblks blocks,

               f.ktfbfefno,

               ktfbfetsn

          from sys.x$ktfbfe f) fet2

 where fet2.file_id = tsfi.relfile#

   and fet2.ts# = tsfi.ts# /*此查询需SYSDBA权限*/ ;

Explained

select * from  table(dbms_xplan.display);

PLAN_TABLE_OUTPUT
---------------------------------------------------------------------------------
Plan hash value: 717737944

---------------------------------------------------------------------------------
| Id  | Operation            | Name     | Rows  | Bytes | Cost (%CPU)| Time     |
---------------------------------------------------------------------------------
|   0 | SELECT STATEMENT     |          |    20 |  1560 |     9  (12)| 00:00:01 |
|*  1 |  HASH JOIN           |          |    20 |  1560 |     9  (12)| 00:00:01 |
|*  2 |   HASH JOIN          |          |     4 |   104 |     6  (17)| 00:00:01 |
|   3 |    TABLE ACCESS FULL | FILE$    |     4 |    36 |     2   (0)| 00:00:01 |
|*  4 |    TABLE ACCESS FULL | TS$      |     5 |    85 |     3   (0)| 00:00:01 |
|   5 |   VIEW               |          |   101 |  5252 |     3   (0)| 00:00:01 |
|   6 |    UNION-ALL         |          |       |       |            |          |
|   7 |     TABLE ACCESS FULL| FET$     |     1 |    52 |     3   (0)| 00:00:01 |
|   8 |     FIXED TABLE FULL | X$KTFBFE |   100 |  5200 |     0   (0)| 00:00:01 |
---------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - access("FET2"."FILE_ID"="FI"."RELFILE#" AND
              "FET2"."TS#"="TS"."TS#")
   2 - access("TS"."TS#"="FI"."TS#")
   4 - filter("TS"."ONLINE$"=1 OR "TS"."ONLINE$"=4)

/*改写后可以大幅减少逻辑读从而提高性能*/

/*可以建立DBA_FREE_SPACE功能相同的替代品,并代入到表空间使用率的脚本中*/
CREATE OR REPLACE VIEW DBA_FREE_SPACE_NEW (
  TABLESPACE_NAME,
  FILE_ID,
  BLOCK_ID,
  BYTES,
  BLOCKS,
  RELATIVE_FNO
) AS
select /*+use_hash (tsfi, fet2 ) */
 tsfi.tablespace_name,
 tsfi.file_id,
 fet2.block_id,
 tsfi.blocksize * fet2.blocks,
 fet2.blocks,
 tsfi.relfile#
  from (select /*+ use_hash ( ts, fi ) */
         ts.name      tablespace_name,
         fi.file#     file_id,
         ts.BLOCKSIZE,
         fi.relfile#,
         ts.ts#
          from sys.ts$ ts, sys.file$ fi
         where ts.ts# = fi.ts#
           and ts.online$ in (1, 4)) tsfi,
       (select f.block# block_id, f.length blocks, f.file# file_id, f.ts#
          from sys.fet$ f
        union all
        select f.ktfbfebno  block_id,
               f.ktfbfeblks blocks,
               f.ktfbfefno,
               ktfbfetsn
          from sys.x$ktfbfe f) fet2
 where fet2.file_id = tsfi.relfile#
   and fet2.ts# = tsfi.ts#  /*建此视图需SYSDBA权限*/ ;

Segment in recyclebin? Is it free?

考过10g ocp的朋友大概都看到过这样的问题,回收站中的对象所占空间是否算作free space?

纸上得来终觉浅,我们实地考察一下:

SQL> set long 99999999;
/*DBA_FREE_SPACE视图列出了数据库中所有表空间上空闲的区间,利用该视图我们可以计算表空间使用率等
注意该视图不会列出本地管理模式中offline的数据文件(或表空间)上的相关区间信息*/

SQL> select text from dba_views where view_name='DBA_FREE_SPACE';

TEXT
--------------------------------------------------------------------------------
select ts.name, fi.file#, f.block#,
       f.length * ts.blocksize, f.length, f.file#
from sys.ts$ ts, sys.fet$ f, sys.file$ fi
where ts.ts# = f.ts#
  and f.ts# = fi.ts#
  and f.file# = fi.relfile#
  and ts.bitmapped = 0
union all
select /*+ ordered use_nl(f) use_nl(fi) */
       ts.name, fi.file#, f.ktfbfebno,
       f.ktfbfeblks * ts.blocksize, f.ktfbfeblks, f.ktfbfefno
from sys.ts$ ts, sys.x$ktfbfe f, sys.file$ fi
where ts.ts# = f.ktfbfetsn
  and f.ktfbfetsn = fi.ts#
  and f.ktfbfefno = fi.relfile#
  and ts.bitmapped <> 0 and ts.online$ in (1,4) and ts.contents$ = 0
union all
select /*+ ordered use_nl(u) use_nl(fi) */
       ts.name, fi.file#, u.ktfbuebno,
       u.ktfbueblks * ts.blocksize, u.ktfbueblks, u.ktfbuefno
from sys.recyclebin$ rb, sys.ts$ ts, sys.x$ktfbue u, sys.file$ fi
where ts.ts# = rb.ts#
  and rb.ts# = fi.ts#
  and u.ktfbuefno = fi.relfile#
  and u.ktfbuesegtsn = rb.ts#
  and u.ktfbuesegfno = rb.file#
  and u.ktfbuesegbno = rb.block#
  and ts.bitmapped <> 0 and ts.online$ in (1,4) and ts.contents$ = 0
union all
select ts.name, fi.file#, u.block#,
       u.length * ts.blocksize, u.length, u.file#
from sys.ts$ ts, sys.uet$ u, sys.file$ fi, sys.recyclebin$ rb
where ts.ts# = u.ts#
  and u.ts# = fi.ts#
  and u.segfile# = fi.relfile#
  and u.ts# = rb.ts#
  and u.segfile# = rb.file#
  and u.segblock# = rb.block#
  and ts.bitmapped = 0

/*可以看到后2个子查询链接中存在recyclebin$基表*/

SQL> show user;
User is "system"

SQL> purge recyclebin;

Done

SQL> create table YOUYUS tablespace users as select * from dba_objects;

Table created

SQL> select sum(bytes) from dba_free_space where tablespace_name='USERS';

SUM(BYTES)
----------
    851968

SQL> drop table YOUYUS;

Table dropped

SQL> col ORIGINAL_NAME   for a10;
SQL> col ts_name for a10;
SQL> select original_name,operation,type,ts_name,space from dba_recyclebin;

ORIGINAL_N OPERATION TYPE                      TS_NAME         SPACE
---------- --------- ------------------------- ---------- ----------
YOUYUS     DROP      TABLE                     USERS            1152
/* 这里的SPACE单位是standard block size,1152 * 8k=9216k */

SQL> select sum(bytes)  from dba_free_space where tablespace_name='USERS';

SUM(BYTES)
----------
  10289152
/* 可以看到YOUYUS表被回收后,USERS表空间上的FREE EXTENT空间也随之增长了;10289152-851968=9216k 与YOUYUS表的大小吻合*/

col name for a10;
/*通过以下查询可以发现数据库中本地管理模式表空间上已被回收对象可以被覆盖重用的区间信息*/
select /*+ ordered use_nl(u) use_nl(fi) */
       ts.name, fi.file#, u.ktfbuebno,
       u.ktfbueblks * ts.blocksize, u.ktfbueblks, u.ktfbuefno
from sys.recyclebin$ rb, sys.ts$ ts, sys.x$ktfbue u, sys.file$ fi
where ts.ts# = rb.ts#
  and rb.ts# = fi.ts#
  and u.ktfbuefno = fi.relfile#
  and u.ktfbuesegtsn = rb.ts#
  and u.ktfbuesegfno = rb.file#
  and u.ktfbuesegbno = rb.block#
  and ts.bitmapped <> 0 and ts.online$ in (1,4) and ts.contents$ = 0;
NAME            FILE#  KTFBUEBNO U.KTFBUEBLKS*TS.BLOCKSIZE KTFBUEBLKS  KTFBUEFNO
---------- ---------- ---------- ------------------------- ---------- ----------
USERS               4        184                     65536          8          4
USERS               4        192                     65536          8          4
USERS               4        200                     65536          8          4
USERS               4        208                     65536          8          4
USERS               4        216                     65536          8          4
USERS               4        224                     65536          8          4
USERS               4        232                     65536          8          4

So We can reuse segment space which resided in recyclebin!
That' great!

ora-600 [17182]错误一例

这是一套古老的系统,SUNOS 5.8,Oracle 8.1.7.4。最近老革命途遇新问题,告警日志烽烟掠起:

Errors in file /u01/app/oracle/admin/CULPRODB/udump/culprodb_ora_7913.trc:
ORA-00600: internal error code, arguments: [17182], [32438472], [], [], [], [], [], []
Thu Jul 15 16:19:29 2010
Errors in file /u01/app/oracle/admin/CULPRODB/udump/culprodb_ora_7913.trc:
ORA-00600: internal error code, arguments: [17182], [32438472], [], [], [], [], [], []
Thu Jul 15 16:19:30 2010
Errors in file /u01/app/oracle/admin/CULPRODB/udump/culprodb_ora_7913.trc:
ORA-00600: internal error code, arguments: [17182], [32438472], [], [], [], [], [], []

如果你像我一样对600着迷,那么点击这里欣赏一下这个trace文件。报错期间运行的SQL及调用栈信息:

ksedmp: internal or fatal error
ORA-00600: internal error code, arguments: [17182], [32438472], [], [], [], [], [], []
Current SQL statement for this session:
select * from olsuser.cardmaster where cm_card_no between '2336330010201570013' and '2336330010201580004' union
select * from olsuser.cardmaster where cm_card_no between '2336330012402300018' and '2336330012402310009' union
select * from olsuser.cardmaster where cm_card_no between '2336330052400220016' and '2336330052400230007' union
select * from olsuser.cardmaster where cm_card_no between '2336330015103900012' and '2336330015138100032' union
select * from olsuser.cardmaster where cm_card_no between '2336330055100910018' and '2336330055100920009'
----- Call Stack Trace -----
calling                   call     entry
location                  type     point
--------------------      -------- --------------------
ksedmp()+220              CALL     ksedst()+0
kgeriv()+268              PTR_CALL 0000000000000000
kgesiv()+140              CALL     kgeriv()+0
kgesic1()+32              CALL     kgesiv()+0
kghfrf()+204              CALL     kgherror()+0
kkscls()+1592             CALL     kghfrf()+0
opicca()+248              CALL     kkscls()+0
opiclo()+8                CALL     opicca()+0
kpoclsa()+60              CALL     opiclo()+0
opiodr()+2540             PTR_CALL 0000000000000000
ttcpip()+5676             PTR_CALL 0000000000000000
opitsk()+2408             CALL     ttcpip()+0
opiino()+2080             CALL     opitsk()+0
opiodr()+2540             PTR_CALL 0000000000000000
opidrv()+1656             CALL     opiodr()+0
sou2o()+16                CALL     opidrv()+0
main()+172                CALL     sou2o()+0
_start()+380              CALL     main()+0
/*8.1.7中stack trace还附带着寄存器信息,但我们可读不懂:)  */

opicca->kkscls->kghfrf->kgherror(heap层报错)->kgesic1。问题主要发生在调用kghfrf函数的时候,《famous summary stack trace from Oracle Version 8.1.7.4.0 Bug Note》 一文罗列了Oracle的一些stack summary,其中kghfrx函数的作用是”Free extent. This is called when a heap is unpinned to request that it”;可以猜测kghfrf函数是用来释放某种内存结构的。在MOS上输入”kghfrf 8.1.7.4″关键词,可以找到Note 291936.1:

ORA-00600 [17182] on Oracle 8.1.7.4.0 After a CTRL-C or Client Termination
Applies to:
Oracle Server – Enterprise Edition – Version: 8.1.7.4
This problem can occur on any platform.
Checked for relevance on 06-Mar-2007

Oracle RDBMS Server Versions prior to 9i
Symptoms
1. Intermittent heap corruptions errors like ORA-00600 [17182] are reported in the alert.log file.

2. There is no impact to the database other than the process which encounters the errors getting killed.

3. From the trace file generated for this ORA-00600 error, check if the top few functions are :

kgherror kghfrf kkscls opicca

Cause
If the trace file shows that kkscls calls kghfrf, then it is related to:

Bug 2281320 — ORA-600[17182] POSSIBLE AFTER CTRL-C OR CLIENT DEATH
Solution
The problem is when we call kghfrf to free a chunk of memory, we expect that this chunk to have been allocated from the Heap Memory and hence have a valid header, although internally we have used Frame Memory managed chunk. As a result, kghfrf errors out with the “Bagic Magic Number” in the Memory Chunk header error message.

If you are running Oracle 8174, encounter this ORA-00600 [17182], and the call stack indicates the following functions { kgherror kghfrf kkscls }, then download and apply Patch 2281320 from MetaLink.

This issue has been fixed in Oracle Server 8.1.7.5 and later versions.

Note 2281320.8 is not limited to dblinks and can occur during normal database operation as well.

该文档叙述描述在9i以前版本中可能因堆损坏而出现该ORA-00600 [17182]错误,该错误不会导致致命问题或数据库损坏,最坏的情况是遭遇该错误的服务进程被杀死。与该问题匹配的主要依据是stack trace为kgherror kghfrf kkscls opicca,同我们的实际情况一致。可以通过打上one-off patch 2281320或者升级到8.1.7.5来避免该内部错误的发生,当然也可以置之不理,显然它不会造成太大的麻烦。
此外kghfrf函数用以释放内存chunk,Oracle development起初以为所有这些可能被释放的chunk都是从堆内存中分配而来,因此都该有一个有效的header;而实际上它们可能是以帧式内存管理的chunk。kghfrf因读取到这种chunk header中的错误幻数(Bagic Magic Number)而误入歧途了。

如何公开Oracle trace文件?

隐式参数_trace_files_public决定了Oracle产生的trace文件是否公开,该参数默认值为FALSE,也就是非DBA/OINSTALL组的用户是没有权限读取数据库产生的trace文件的;在某些场合中我们需要让非DBA组的用户也能访问trace文件,就可以通过修改该参数实现。请看下面的例子:

SQL> select * from v$version;

BANNER
----------------------------------------------------------------
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
PL/SQL Release 10.2.0.4.0 - Production
CORE    10.2.0.4.0      Production
TNS for Linux: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production

SQL> col name for a20
SQL> col value for a20
SQL> col describ for a40
SQL> SELECT x.ksppinm NAME, y.ksppstvl VALUE, x.ksppdesc describ
  2   FROM SYS.x$ksppi x, SYS.x$ksppcv y
  3   WHERE x.inst_id = USERENV ('Instance')
  4   AND y.inst_id = USERENV ('Instance')
  5   AND x.indx = y.indx
  6  AND x.ksppinm LIKE '%_trace_files_public%'
  7  order by x.ksppinm;

NAME                 VALUE                DESCRIB
-------------------- -------------------- ----------------------------------------
_trace_files_public  FALSE                Create publicly accessible trace files

SQL> oradebug setmypid;
Statement processed.
SQL> oradebug ipc;
Information written to trace file.
SQL> oradebug tracefile_name;
/s01/10gdb/admin/YOUYUS/udump/youyus_ora_10268.trc
SQL> !ls -l /s01/10gdb/admin/YOUYUS/udump/youyus_ora_10268.trc
-rw-r----- 1 maclean oinstall 4206 Aug 11 20:51 /s01/10gdb/admin/YOUYUS/udump/youyus_ora_10268.trc
/*所产生的trace文件权限为640,非oinstall组用户无权限读取该文件*/

SQL> alter system set "_trace_files_public"=true;
alter system set "_trace_files_public"=true
                 *
ERROR at line 1:
ORA-02095: specified initialization parameter cannot be modified
/*修改该参数需要重启实例*/

SQL> alter system set "_trace_files_public"=true scope=spfile;

System altered.

SQL> startup force;
ORACLE instance started.

Total System Global Area 1577058304 bytes
Fixed Size                  2084264 bytes
Variable Size             922747480 bytes
Database Buffers          637534208 bytes
Redo Buffers               14692352 bytes
Database mounted.
Database opened.

SQL> oradebug setmypid;
Statement processed.
SQL> oradebug ipc;
Information written to trace file.
SQL> oradebug tracefile_name;
/s01/10gdb/admin/YOUYUS/udump/youyus_ora_10430.trc
SQL> ! ls -l /s01/10gdb/admin/YOUYUS/udump/youyus_ora_10430.trc
-rw-r--r-- 1 maclean oinstall 5471 Aug 11 20:54 /s01/10gdb/admin/YOUYUS/udump/youyus_ora_10430.trc
/*other组用户也具有了读权限*/

SQL> ! ls -l /s01/10gdb/admin/YOUYUS/
total 24
drwxr-x--- 2 maclean oinstall 4096 Aug 11 20:56 adump
drwxr-x--- 2 maclean oinstall 4096 Aug 11 20:54 bdump
drwxr-x--- 2 maclean oinstall 4096 Aug  5 21:35 cdump
drwxr-x--- 2 maclean oinstall 4096 Aug  5 21:36 dpdump
drwxr-x--- 2 maclean oinstall 4096 Aug  5 21:37 pfile
drwxr-x--- 2 maclean oinstall 4096 Aug 11 20:54 udump
/*请注意修改_trace_files_public为true,并不会修改trace所在目录的权限,Oracle默认建立bdump/udump等trace目录时分配的权限为750,other组用户无法进入这些目录,需要修改目录权限为755,即o+r+x*/

SQL> ! chmod o+r+x /s01/10gdb/admin/YOUYUS/*dump

SQL>  ! ls -l /s01/10gdb/admin/YOUYUS/
total 24
drwxr-xr-x 2 maclean oinstall 4096 Aug 11 20:56 adump
drwxr-xr-x 2 maclean oinstall 4096 Aug 11 20:54 bdump
drwxr-xr-x 2 maclean oinstall 4096 Aug  5 21:35 cdump
drwxr-xr-x 2 maclean oinstall 4096 Aug  5 21:36 dpdump
drwxr-x--- 2 maclean oinstall 4096 Aug  5 21:37 pfile
drwxr-xr-x 2 maclean oinstall 4096 Aug 11 20:54 udump

/*需要注意的另一点是修改_trace_files_public参数并不会引起既有的trace文件的权限被修改,典型的例子是alert log告警日志*/
[maclean@rh2 bdump]$ ls -l
total 20
-rw-r----- 1 maclean oinstall 12971 Aug 11 21:17 alert_YOUYUS.log
-rw-r--r-- 1 maclean oinstall   690 Aug 11 21:12 youyus_lgwr_10514.trc

SQL> SELECT x.ksppinm NAME, y.ksppstvl VALUE, x.ksppdesc describ
  2   FROM SYS.x$ksppi x, SYS.x$ksppcv y
  3   WHERE x.inst_id = USERENV ('Instance')
  4   AND y.inst_id = USERENV ('Instance')
  5   AND x.indx = y.indx
  6  AND x.ksppinm LIKE '%_trace_files_public%'
  7  order by x.ksppinm;

NAME                 VALUE                DESCRIB
-------------------- -------------------- ----------------------------------------
_trace_files_public  FALSE                Create publicly accessible trace files

SQL> alter system set "_trace_files_public"=true scope=spfile;

System altered.

SQL> startup force;
ORACLE instance started.

Total System Global Area 1577058304 bytes
Fixed Size                  2084264 bytes
Variable Size             922747480 bytes
Database Buffers          637534208 bytes
Redo Buffers               14692352 bytes
Database mounted.
Database opened.
SQL> !ls -l
total 32
-rw-r----- 1 maclean oinstall 21189 Aug 11 21:20 alert_YOUYUS.log
-rw-r--r-- 1 maclean oinstall   690 Aug 11 21:12 youyus_lgwr_10514.trc
-rw-r--r-- 1 maclean oinstall   690 Aug 11 21:20 youyus_lgwr_11136.trc

11g新特性之IO校准(IO Calibration)

IO校准(IO Calibration)特性可以帮助我们了解存储系统的真实性能,以进一步判断I/O性能问题是由数据库还是存储系统自身引起的。I/O校准特性(IO Calibration)通过对Oracle数据文件的随机I/O访问存储介质,其结论值更符合数据库IO性能的真实情况。
在使用该特性前,我们要确保满足以下条件:

  • 调用该存储过程需要用到SYSDBA权限
  • TIME_STATISTICS 参数为true:

SQL> show parameter timed_statistics;

NAME TYPE VALUE
———————————— ———– ——————————
timed_statistics boolean TRUE

  • 必须打开异步IO;注意在使用文件系统时,FILESYSTEMIO_OPTIONS需设为SETALL或ASYNC,否则Oracle不会启用异步IO。
  • 可以通过以下查询检验是否启用了异步IO:
SQL> SELECT NAME, ASYNCH_IO
2    FROM V$DATAFILE F, V$IOSTAT_FILE I
3   WHERE F.FILE# = I.FILE_NO
4     AND FILETYPE_NAME = 'Data File';

NAME                                                                             ASYNCH_IO
-------------------------------------------------------------------------------- ---------
D:\TOOLS\ADMINSTRATORG\ORADATA\PROD\DATAFILE\O1_MF_SYSTEM_65DN8HXT_.DBF       ASYNC_ON
D:\TOOLS\ADMINSTRATORG\ORADATA\PROD\DATAFILE\O1_MF_SYSAUX_65DN8J18_.DBF       ASYNC_ON
D:\TOOLS\ADMINSTRATORG\ORADATA\PROD\DATAFILE\O1_MF_UNDOTBS1_65DN8J1S_.DBF     ASYNC_ON
D:\TOOLS\ADMINSTRATORG\ORADATA\PROD\DATAFILE\O1_MF_USERS_65DN8J2X_.DBF        ASYNC_ON

IO Calibration特性可以通过DBMS_RESOURCE_MANAGER.CALIBRATE_IO存储过程调用;该过程会对Oracle数据文件引发一系列IO敏感的只读工作负载(由1MB大小的随机IO组成),从而判断存储系统所能持续的最大IOPS(每秒最大IO请求数)和MBPS(每秒IO传输速率)。为了使结果更具代表性,应当保持IO Calibration测试过程中整个数据库是空闲的,没有其他IO负载损耗。

让我们具体来看一下CALIBRATE_IO存储过程的调用方法:

 -- Initiate an I/O calibration
 --
 -- Input arguments:
 --  num_physical_disks   - Approximate number of physical disks in
 --                         the database storage
 --  max_latency          - Maximum tolerable latency in milliseconds for
 --                         database-block-sized IO requests
 --
 -- Output arguments:
 --  max_iops       - Maximum number of I/O requests per second that can be
 --                   sustained.  The I/O requests are randomly-distributed,
 --                   database-block-sized reads.
 --  max_mbps       - Maximum throughput of I/O that can be sustained,
 --                   expressed in megabytes per second. The I/O requests
 --                   are randomly-distributed, 1 megabyte reads.
 --  actual_latency - Average latency of database-block-sized I/O
 --                   requests at "max_iops" rate, expressed in milliseconds.
 --
  PROCEDURE calibrate_io (
   num_physical_disks  IN  PLS_INTEGER DEFAULT 1,
   max_latency         IN  PLS_INTEGER DEFAULT 20,
   max_iops            OUT PLS_INTEGER,
   max_mbps            OUT PLS_INTEGER,
   actual_latency      OUT PLS_INTEGER
   );

其中输入参数num_physical_disks用以指定数据库存储所用物理磁盘的近似数;max_latency指定了客户所能容忍的最大IO 延迟时间,单位为ms;一般我们认为IO平均等待在10ms左右是一种较好的表现,远大于这个数字往往说明IO负载过高了,这里我们假定15ms是我们的deadline。

SQL> set serveroutput on;
SQL> DECLARE
  2    lat  INTEGER;
  3    iops INTEGER;
  4    mbps INTEGER;
  5  BEGIN
  6  -- DBMS_RESOURCE_MANAGER.CALIBRATE_IO (disk_count,max_latency , iops, mbps, lat);
  7     DBMS_RESOURCE_MANAGER.CALIBRATE_IO (2, 15, iops, mbps, lat);
  8
  9    DBMS_OUTPUT.PUT_LINE ('max_iops = ' || iops);
 10    DBMS_OUTPUT.PUT_LINE ('latency  = ' || lat);
 11    dbms_output.put_line('max_mbps = ' || mbps);
 12  end;
 13  /

max_iops = 127
latency  = 15
max_mbps = 38

PL/SQL procedure successfully completed
/*平均延迟为15ms时,最大iops为127,mbps为38*/

/*执行过程中也可以通过V$IO_CALIBRATION_STATUS视图了解进度*/
SQL> select * from V$IO_CALIBRATION_STATUS;

STATUS        CALIBRATION_TIME
------------- --------------------------------------------------------------------------------
IN PROGRESS   11-8月 -10 12.02.35.121 下午

SQL> alter session set nls_timestamp_format='HH24:MI';

Session altered
SQL> col start_time for a10;
SQL> col end_time for a10;
SQL> select * from DBA_RSRC_IO_CALIBRATE;

START_TIME END_TIME     MAX_IOPS   MAX_MBPS  MAX_PMBPS    LATENCY NUM_PHYSICAL_DISKS
---------- ---------- ---------- ---------- ---------- ---------- ------------------
12:55      12:59             127         38         14         15                  2
/*DBA_RSRC_IO_CALIBRATE视图记录了IO CALIBRATION的历史信息*/

[gview file=”http://askmac.cn/wp-content/uploads/resource/calibrate_io.pdf”]

11g中AWR新快照视图

DBA_HIST_IOSTAT_DETAIL视图记录了不同类型和组件功能所作IO的统计数据。这个视图的数据来自于V$IOSTAT_FILE和V$IOSTAT_FUNCTION 2个动态视图的快照。值得一提的是V$IOSTAT_FILE,它是11g中新引入的动态性能视图:

SQL> select filetype_name, asynch_io, access_method, retries_on_error
  2    from v$iostat_file;

FILETYPE_NAME                ASYNCH_IO ACCESS_METH RETRIES_ON_ERROR
---------------------------- --------- ----------- ----------------
Other                        ASYNC_OFF OS_LIB                     0
Control File                 ASYNC_OFF                            0
Log File                     ASYNC_OFF                            0
Archive Log                  ASYNC_OFF                            0
Data File Backup             ASYNC_OFF                            0
Data File Incremental Backup ASYNC_OFF                            0
Archive Log Backup           ASYNC_OFF                            0
Data File Copy               ASYNC_OFF                            0
Flashback Log                ASYNC_OFF                            0
Data Pump Dump File          ASYNC_OFF                            0
Data File                    ASYNC_ON  OS_LIB                     0
/*ASYNCH_IO列很好地标示了Oracle对于该类型文件是否启用了异步IO,这样我们就无需通过SYSTEM CALL TRACE来确定这一点了;
 retries_on_error累计了物理读取的失败次数,对我们发现磁盘坏道有一定帮助。目前的11.2.0.1官方Reference没有ACCESS_METHOD列的资料,猜想可能分为OS_LIB和ASM及Exdata等多种情况,有待验证。

我们回过头来继续讨论DBA_HIST_IOSTAT_DETAIL视图!

SQL> desc dba_hist_iostat_detail;
Name                  Type         Nullable Default Comments
--------------------- ------------ -------- ------- --------
SNAP_ID               NUMBER
DBID                  NUMBER
INSTANCE_NUMBER       NUMBER
FUNCTION_ID           NUMBER
FUNCTION_NAME         VARCHAR2(30)
FILETYPE_ID           NUMBER
FILETYPE_NAME         VARCHAR2(30)
SMALL_READ_MEGABYTES  NUMBER
SMALL_WRITE_MEGABYTES NUMBER
LARGE_READ_MEGABYTES  NUMBER
LARGE_WRITE_MEGABYTES NUMBER
SMALL_READ_REQS       NUMBER
SMALL_WRITE_REQS      NUMBER
LARGE_READ_REQS       NUMBER
LARGE_WRITE_REQS      NUMBER
NUMBER_OF_WAITS       NUMBER
WAIT_TIME             NUMBER

SQL> col SMALL_READ_MEGABYTES for 999999;
SQL> col SMALL_WRITE_MEGABYTES for 999999;
SQL> col LARGE_READ_MEGABYTES for 999999;
SQL> col LARGE_WRITE_MEGABYTES for 999999;
SQL> col FILETYPE_NAME for a25;
SQL> select snap_id,
  2         function_name,
  3         filetype_name,
  4         SMALL_READ_MEGABYTES,
  5         SMALL_WRITE_MEGABYTES,
  6         LARGE_READ_MEGABYTES,
  7         LARGE_WRITE_MEGABYTES,
  8         WAIT_TIME
  9    from dba_hist_iostat_detail
 10   where rownum < 16;

   SNAP_ID FUNCTION_NAME                  FILETYPE_NAME             SMALL_ SMALL_ LARGE_ LARGE_  WAIT_TIME
---------- ------------------------------ ------------------------- ------ ------ ------ ------ ----------
         1 DBWR                           Control File                   1      0      0      0        310
         1 LGWR                           Control File                   0      0      0      0         94
         1 Others                         Control File                 122     37      0      0      71635
         2 DBWR                           Control File                   1      0      0      0        310
         2 LGWR                           Control File                   0      0      0      0         94
         2 Others                         Control File                 251     77      0      0     159025
         3 Others                         Control File                  14      7      0      0      10339
         4 Others                         Control File                  96     60      0      0      87516
         5 Others                         Control File                 151     96      0      0     139796
         6 DBWR                           Control File                   0      0      0      0         15
         6 Others                         Control File                 210    135      0      0     189114
         7 DBWR                           Control File                   0      0      0      0         15
         7 Others                         Control File                 269    174      0      0     239640
         8 DBWR                           Control File                   0      0      0      0         15
         8 Others                         Control File                 328    213      0      0     288425

15 rows selected

其中SMALL_READ/WRITE代表单块读写,LARGE_READ/WRITE代表多块读写,wait_time的单位是千分之一秒(ms)。

SQL> select snap_id,
  2         function_name,
  3         filetype_name,
  4         SMALL_READ_MEGABYTES,
  5         SMALL_WRITE_MEGABYTES,
  6         LARGE_READ_MEGABYTES,
  7         LARGE_WRITE_MEGABYTES,
  8         WAIT_TIME
  9    from dba_hist_iostat_detail
 10   where filetype_name = 'Control File'
 11     and (LARGE_READ_REQS > 0 or LARGE_WRITE_REQS > 0);

未选定行
/*Oracle对控制文件只做单块读写*/

SQL> col FILETYPE_NAME for a15;
SQL> col function_name for a10;
SQL> select function_name,
  2         filetype_name,
  3         small_read_reqs,
  4         small_write_reqs,
  5         large_read_reqs,
  6         large_write_reqs
  7    from dba_hist_iostat_detail
  8   where filetype_name = 'Log File'
  9  and (SMALL_READ_REQS > 0 or LARGE_READ_REQS > 0);

FUNCTION_N FILETYPE_NAME   SMALL_READ_REQS SMALL_WRITE_REQS LARGE_READ_REQS LARGE_WRITE_REQS
---------- --------------- --------------- ---------------- --------------- ----------------
LGWR       Log File                      4             9140               0               86
LGWR       Log File                      4             2762               0              218
LGWR       Log File                      8             3512               0              222
LGWR       Log File                      8             4304               0              226
LGWR       Log File                      4             1996               0              210
LGWR       Log File                      8             5296               0              252
LGWR       Log File                      8             6016               0              254
LGWR       Log File                      8             7224               0              274
LGWR       Log File                      4            11536               0              232
LGWR       Log File                      8            13320               0              256

SQL> select snap_id,
  2         function_name,
  3         filetype_name,
  4         SMALL_READ_MEGABYTES,
  5         SMALL_WRITE_MEGABYTES,
  6         LARGE_READ_MEGABYTES,
  7         LARGE_WRITE_MEGABYTES,
  8         WAIT_TIME
  9    from dba_hist_iostat_detail
 10   where filetype_name = 'Log File';

   SNAP_ID FUNCTION_NAME                  FILETYPE_NAME             SMALL_ SMALL_ LARGE_ LARGE_  WAIT_TIME
---------- ------------------------------ ------------------------- ------ ------ ------ ------ ----------
         2 LGWR                           Log File                       0     60      0     27         30
        35 LGWR                           Log File                       0     23      0     48          0
         6 LGWR                           Log File                       0     12      0      8          0
         7 LGWR                           Log File                       0     15      0     10          0
         8 LGWR                           Log File                       0     18      0     12          0
        13 LGWR                           Log File                       0      5      0      4          0
        15 LGWR                           Log File                       0      6      0      2          0
        17 LGWR                           Log File                       0      4      0      3          0
        19 LGWR                           Log File                       0     11      0      7          0
        20 LGWR                           Log File                       0     14      0      8          0
        37 LGWR                           Log File                       0     13      0     27          0
        38 LGWR                           Log File                       0     15      0     29          0
        41 LGWR                           Log File                       0     13      0    152         46
        42 LGWR                           Log File                       0     16      0    153         61
        43 LGWR                           Log File                       0     19      0    155         61
        49 LGWR                           Log File                       0      2      0      0          0
         3 LGWR                           Log File                       0      1      0      0          0
         4 LGWR                           Log File                       0      7      0      4          0
         5 LGWR                           Log File                       0      9      0      6          0
        12 LGWR                           Log File                       0      1      0      0          0
/*日志文件在写出时会伴有少量的日志单块读操作,日志文件的写兼有单块写和多块写2种操作*/

另外,你大概和我一样不太喜欢使用OEM界面,不过OEM界面有个很方便的功能就是显示短期内的Avg Active Session Count(AAS)。什么?那你从来没看到过这种东西?下面这张截图大概可以勾起你的回忆:


早在10g时代就有人写了一个显示短期内AAS的脚本,在11g中该脚本得到了简化了:

set echo off;
set verify off;
alter session set nls_date_format='HH24:MI';
select *
  from (select nvl(wait_class, 'CPU') activity,
               trunc(sample_time, 'MI') time
          from v$active_session_history) v pivot(count(*) for activity in('CPU' as
                                                                          "CPU",
                                                                          'Concurrency' as
                                                                          "Concurrency",
                                                                          'System I/O' as
                                                                          "System I/O",
                                                                          'User I/O' as
                                                                          "User I/O",
                                                                          'Administrative' as
                                                                          "Administrative",
                                                                          'Configuration' as
                                                                          "Configuration",
                                                                          'Application' as
                                                                          "Application",
                                                                          'Network' as
                                                                          "Network",
                                                                          'Commit' as
                                                                          "Commit",
                                                                          'Scheduler' as
                                                                          "Scheduler",
                                                                          'Cluster' as
                                                                          "Cluster",
                                                                          'Queueing' as
                                                                          "Queueing",
                                                                          'Other' as
                                                                          "Other"))
 where time > sysdate - interval '&last_min' minute
 order by time;

我们也可以通过ASH查找Oracle中的TOP SESSION和TOP SQL:

/*找出短期内TOP SQL的sql_id和活动历史*/
select ash.SQL_ID,
       sum(decode(ash.session_state, 'ON CPU', 1, 0)) "CPU",
       sum(decode(ash.session_state, 'WAITING', 1, 0)) -
       sum(decode(ash.session_state,
                  'WAITING',
                  decode(en.wait_class, 'User I/O', 1, 0),
                  0)) "WAIT",
       sum(decode(ash.session_state,
                  'WAITING',
                  decode(en.wait_class, 'User I/O', 1, 0),
                  0)) "IO",
       sum(decode(ash.session_state, 'ON CPU', 1, 1)) "TOTAL"
  from v$active_session_history ash, v$event_name en
 where SQL_ID is not NULL
   and en.event# = ash.event#
 group by sql_id
 order by sum(decode(session_state, 'ON CPU', 1, 1)) desc;

SQL_ID               CPU       WAIT         IO      TOTAL
------------- ---------- ---------- ---------- ----------
a01hp0psv0rrh          0          2          7          9
24g90qj2b7ywk          0          5          1          6
2amsp6skc6tjv          0          0          5          5
46quk68k7akpa          0          3          1          4
2ufrf9vk4kcwj          0          0          3          3
1w8m6dwy66ttn          0          0          3          3
8uxr3scz9bmxd          0          0          3          3
6htq3p9j91y0s          0          0          3          3
cvn54b7yz0s8u          0          0          3          3
92f47aa2q2rmd          0          2          1          3

/*找出变量ivl指定分钟内的TOP CPU SESSION*/
Select session_id, count(*)
  from v$active_session_history
 where session_state = 'ON CPU'
   and SAMPLE_TIME > sysdate -(&ivl/(24 * 60))
 group by session_id
 order by count(*) desc;
输入 ivl 的值:  10
原值    4:    and SAMPLE_TIME > sysdate -(&ivl/(24 * 60))
新值    4:    and SAMPLE_TIME > sysdate -(10/(24 * 60))

SESSION_ID   COUNT(*)
---------- ----------
       136          4

/*找出变量ivl指定分钟内TOP WAITING SESSION*/
Select session_id, count(*)
  from v$active_session_history
 where session_state = 'WAITING'
   and SAMPLE_TIME > SYSDATE - (&ivl / (24 * 60))
 group by session_id
 order by count(*) desc;

输入 ivl 的值:  10
原值    4:    and SAMPLE_TIME > SYSDATE - (&ivl / (24 * 60))
新值    4:    and SAMPLE_TIME > SYSDATE - (10 / (24 * 60))

SESSION_ID   COUNT(*)
---------- ----------
         3         11

/*找出短期内的TOP SESSION及活动历史*/
select ash.session_id,
       ash.session_serial#,
       ash.user_id,
       ash.program,
       sum(decode(ash.session_state, 'ON CPU', 1, 0)) "CPU",
       sum(decode(ash.session_state, 'WAITING', 1, 0)) -
       sum(decode(ash.session_state,
                  'WAITING',
                  decode(en.wait_class, 'User I/O', 1, 0),
                  0)) "WAITING",
       sum(decode(ash.session_state,
                  'WAITING',
                  decode(en.wait_class, 'User I/O', 1, 0),
                  0)) "IO",
       sum(decode(session_state, 'ON CPU', 1, 1)) "TOTAL"
  from v$active_session_history ash, v$event_name en
 where en.event# = ash.event#
 group by session_id, user_id, session_serial#, program
 order by sum(decode(session_state, 'ON CPU', 1, 1));

以上脚本完全可以被ashrpt报表所替代,但在短期内做针对检查仍十分有效。

分析Oracle Mutex等待事件

Troubleshooting or analyzing waits on mutex events, i.e. ones that start with “cursor:”, are very similar to each other and below are some guidelines.

There are many bugs related to problems using mutexes in Oracle 10g, the first version where mutexes were introduced. If you are seeing excessive waits on mutexes, a quick fix may be to go back to the library cache latching mechanism. To do this, you can set the parameter _kks_use_mutex_pin=false.

 

Note: For mutex related waits, v$session.blocking_session is not populated in 10.2. However, v$session.blocking_session is populated in 11g R1.

 

To do further analysis, the P2RAW column in v$session gives the blocking session, i.e. the holder SID of the mutex in the upper 8 bytes. It is in hex so it needs to be converted in decimal. The following query provides the blockers with the most sessions blocked behind it as well as converts the P2RAW to an usable SID:

 

select p2raw, to_number(substr(to_char(rawtohex(p2raw)), 1, 8), ‘XXXXXXXX’) sid, count(1) sessions_waiting
from v$session
where event = ‘cursor: pin S wait on X’
group by p2raw, to_number(substr(to_char(rawtohex(p2raw)), 1, 8), ‘XXXXXXXX’);

 

P2RAW                      SID    SESSIONS_WAITING
—————-            —                  —————-
0000001F00000000    31                                    79

 

On 64 bit platforms 8 bytes are used, so the top 4 bytes are the holding session Id (if the mutex is held X), and the bottom 4 bytes are the ref count (if the mutex is held S). On 32 bit platforms 4 bytes are used, so the top 2 bytes are the holding session Id (if the mutex is held X) and the bottom 2 bytes are the ref count (if the mutex is held S).

 

p1 = The mutex Id
This has the same definition as v$mutex_sleep_history.mutex_identifier

p2raw = Holding Session Id | Ref Count

The most significant bytes always store the Holding Session Id (Holding SID). The least significant bytes always store the Ref Count.

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